Fixing unsafe header 'Origin' error in Chrome's xmlHttpRequest

If you are encountering the "unsafe header 'Origin'" error while using the xmlHttpRequest in Chrome, don't worry, there are a few ways to fix it.

First, let's understand what the error means. This error occurs when the server tries to send a response with the "Access-Control-Allow-Origin" header set to "*", but also includes other headers that are not allowed. Chrome considers this to be a security risk and blocks the response.

To fix the error, you can either modify the server's response to only include allowed headers or modify the client-side code to not send the "Origin" header.

If you have access to the server-side code, you can modify the response headers to only include the necessary ones. For example, if you are using PHP, you can use the header() function to set the headers:

<?php
header("Access-Control-Allow-Origin: *");
header("Access-Control-Allow-Methods: POST, GET, OPTIONS");
header("Access-Control-Allow-Headers: Origin, Content-Type, Accept");
?>

If you don't have access to the server-side code or can't modify it, you can modify the client-side code to not include the "Origin" header. For example:

var xhr = new XMLHttpRequest();
xhr.open('GET', 'https://example.com/api/data');
xhr.setRequestHeader('Content-Type', 'application/json');
xhr.setRequestHeader('Accept', 'application/json');
xhr.send();

In this example, we are not setting the "Origin" header, which should prevent the error from occurring.

In summary, the "unsafe header 'Origin'" error in Chrome's xmlHttpRequest can be fixed by either modifying the server's response headers or modifying the client-side code to not send the "Origin" header.

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