# Python: Efficiently Obtain All Divisors of a Number - Best Method

When it comes to obtaining all divisors of a number efficiently in Python, there are a few different approaches you can take. However, one of the most efficient methods is to use a simple loop that iterates through all numbers from 1 to the square root of the given number.

```
import math
def get_divisors(n):
divisors = []
for i in range(1, int(math.sqrt(n))+1):
if n % i == 0:
divisors.append(i)
if i != n // i:
divisors.append(n // i)
return divisors
```

Let's break down how this code works. First, we import the math module so that we can use the `sqrt`

function to obtain the square root of the given number. Next, we define a function called `get_divisors`

that takes in a number `n`

.

Inside the function, we initialize an empty list called `divisors`

to hold all of the divisors we find. We then iterate through all numbers from 1 to the square root of `n`

, checking if each number is a divisor of `n`

using the modulo operator (`%`

).

If a number is a divisor, we add it to our list of divisors. We also check if the divisor is not equal to the square root of `n`

, in which case we add the corresponding factor to our list as well. This ensures that we capture all divisors of `n`

, not just the ones less than the square root.

The use of the `sqrt`

function and the conditional check for the corresponding factor allows us to avoid iterating through all numbers up to `n`

, making this method much more efficient for large numbers.

Overall, if you're looking for a fast and efficient way to obtain all divisors of a number in Python, this method using a simple loop and the `sqrt`

function is definitely one of the best options available.

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