# Python: Efficiently Obtain All Divisors of a Number - Best Method

When it comes to obtaining all divisors of a number efficiently in Python, there are a few different approaches you can take. However, one of the most efficient methods is to use a simple loop that iterates through all numbers from 1 to the square root of the given number.

``````
import math

def get_divisors(n):
divisors = []
for i in range(1, int(math.sqrt(n))+1):
if n % i == 0:
divisors.append(i)
if i != n // i:
divisors.append(n // i)
return divisors
``````

Let's break down how this code works. First, we import the math module so that we can use the `sqrt` function to obtain the square root of the given number. Next, we define a function called `get_divisors` that takes in a number `n`.

Inside the function, we initialize an empty list called `divisors` to hold all of the divisors we find. We then iterate through all numbers from 1 to the square root of `n`, checking if each number is a divisor of `n` using the modulo operator (`%`).

If a number is a divisor, we add it to our list of divisors. We also check if the divisor is not equal to the square root of `n`, in which case we add the corresponding factor to our list as well. This ensures that we capture all divisors of `n`, not just the ones less than the square root.

The use of the `sqrt` function and the conditional check for the corresponding factor allows us to avoid iterating through all numbers up to `n`, making this method much more efficient for large numbers.

Overall, if you're looking for a fast and efficient way to obtain all divisors of a number in Python, this method using a simple loop and the `sqrt` function is definitely one of the best options available.

Click to rate this post!
[Total: 0 Average: 0]

Related posts

Go up

Below we inform you of the use we make of the data we collect while browsing our pages. You can change your preferences at any time by accessing the link to the Privacy Area that you will find at the bottom of our main page. More Information